Difference of Two Squares

Difference of Two Squares

We have seen that \((ax + b)(ax - b)\) can be expanded to \({a}^{2}{x}^{2} - {b}^{2}\).

Therefore \({a}^{2}{x}^{2} - {b}^{2}\) can be factorised as \((ax + b)(ax - b)\).

For example, \({x}^{2} - 16\) can be written as \({x}^{2} - {4}^{2}\) which is a difference of two squares. Therefore, the factors of \({x}^{2} - 16\) are \((x - 4)\) and \((x + 4)\).

To spot a difference of two squares, look for expressions:

  • consisting of two terms;

  • with terms that have different signs (one positive, one negative);

  • with each term a perfect square.

For example: \({a}^{2} - 1\); \(4{x}^{2} - {y}^{2}\); \(-49 + {p}^{4}\).

The following video explains factorising the difference of two squares.

Example

Question

Factorise: \(3a({a}^{2} - 4) - 7({a}^{2} - 4)\).

Take out the common factor \(({a}^{2} - 4)\)

\[3a({a}^{2} - 4) - 7({a}^{2} - 4) = ({a}^{2} - 4)(3a - 7)\]

Factorise the difference of two squares \(({a}^{2} - 4)\)

\[({a}^{2} - 4)(3a - 7) = (a - 2)(a + 2)(3a - 7)\]

This lesson is part of:

Algebraic Expressions Overview

View Full Tutorial

Track Your Learning Progress

Sign in to unlock unlimited practice exams, tutorial practice quizzes, personalized weak area practice, AI study assistance with Lexi, and detailed performance analytics.