Solving Quadratic Equations Using the Zero Product Property
Solving Quadratic Equations Using the Zero Product Property
We will first solve some quadratic equations by using the Zero Product Property. The Zero Product Property says that if the product of two quantities is zero, it must be that at least one of the quantities is zero. The only way to get a product equal to zero is to multiply by zero itself.
Zero Product Property
If \(a·b=0\), then either \(a=0\) or \(b=0\) or both.
We will now use the Zero Product Property, to solve a quadratic equation.
Example: How to Use the Zero Product Property to Solve a Quadratic Equation
Solve: \(\left(x+1\right)\left(x-4\right)=0\).
Solution
We usually will do a little more work than we did in this last example to solve the linear equations that result from using the Zero Product Property.
Example
Solve: \(\left(5n-2\right)\left(6n-1\right)=0\).
Solution
| \(\left(5n-2\right)\left(6n-1\right)=0\) | ||
| Use the Zero Product Property to set each factor to 0. | \(5n-2=0\) | \(6n-1=0\) |
| Solve the equations. | \(n=\frac{2}{5}\) | \(n=\frac{1}{6}\) |
| Check your answers. | ||
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This image shows the steps for solving (5 n – 2)(6 n – 1) = 0. First, use the zero factor property to set each factor equal to 0, 5 n – 2 = 0 or 6 n – 1 = 0. Then, solve the equations, n = 2/5 or n = 1/6. Finally, check the answers by substituting the two solutions back into the original equation. |
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Notice when we checked the solutions that each of them made just one factor equal to zero. But the product was zero for both solutions.
Example
Solve: \(3p\left(10p+7\right)=0\).
Solution
| \(\phantom{\rule{1.2em}{0ex}}3p\left(10p+7\right)=0\) | ||
| Use the Zero Product Property to set each factor to 0. | \(3p=0\) | \(10p+7=0\phantom{\rule{1.6em}{0ex}}\) |
| Solve the equations. | \(p=0\) | \(10p=-7\phantom{\rule{0.9em}{0ex}}\) |
| \(p=-\frac{7}{10}\) | ||
| Check your answers. | ||
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This image shows the steps for solving 3 p (10 p + 7) = 0. The first step is using the zero product property to set each factor equal to 0, 3p = 0 or 10 p + 7 = 0. The next step is solving both equations, p = 0 or p = negative 7/10. Finally, check the solutions by substituting the answers into the original equation. |
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It may appear that there is only one factor in the next example. Remember, however, that \({\left(y-8\right)}^{2}\) means \(\left(y-8\right)\left(y-8\right)\).
Example
Solve: \({\left(y-8\right)}^{2}=0\).
Solution
| \({\left(y-8\right)}^{2}=0\) | ||
| Rewrite the left side as a product. | \(\left(y-8\right)\left(y-8\right)=0\) | |
| Use the Zero Product Property and set each factor to 0. | \(y-8=0\) | \(y-8=0\) |
| Solve the equations. | \(y=8\) | \(y=8\) |
| When a solution repeats, we call it a double root. | ||
| Check your answer. | ||
This image above shows the steps for solving the equation (y – 8) squared = 0. The first step is to write the left hand side as a product, (y – 8)(y – 8) = 0. The next step is using the zero product property and set each factor equal to 0, y – 8 = 0 and y – 8 -= 0. Solve both equations, y = 8 and y = 8. When the solution repeats, it is a double root. Finally, check the solution by substituting back into the original equation.
This lesson is part of:
Factoring and Factorisation I