Choosing the Most Convenient Method to Solve a System of Linear Equations
Choosing the Most Convenient Method to Solve a System of Linear Equations
When you will have to solve a system of linear equations in a later math class, you will usually not be told which method to use. You will need to make that decision yourself. So you’ll want to choose the method that is easiest to do and minimizes your chance of making mistakes.
Example
For each system of linear equations decide whether it would be more convenient to solve it by substitution or elimination. Explain your answer.
(a) \(\begin{array}{c}3x+8y=40\hfill \\ 7x-4y=-32\hfill \end{array}\)
(b) \(\begin{array}{c}5x+6y=12\hfill \\ y=\frac{2}{3}x-1\hfill \end{array}\)
Solution
(a) \(\begin{array}{c}3x+8y=40\hfill \\ 7x-4y=-32\hfill \end{array}\)
Since both equations are in standard form, using elimination will be most convenient.
(b) \(\begin{array}{c}5x+6y=12\hfill \\ y=\frac{2}{3}x-1\hfill \end{array}\)
Since one equation is already solved for y, using substitution will be most convenient.
Key Concepts
- To Solve a System of Equations by Elimination
- Write both equations in standard form. If any coefficients are fractions, clear them.
- Make the coefficients of one variable opposites.
- Decide which variable you will eliminate.
- Multiply one or both equations so that the coefficients of that variable are opposites.
- Add the equations resulting from Step 2 to eliminate one variable.
- Solve for the remaining variable.
- Substitute the solution from Step 4 into one of the original equations. Then solve for the other variable.
- Write the solution as an ordered pair.
- Check that the ordered pair is a solution to both original equations.
This lesson is part of:
Systems of Linear Equations I