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Earlier discussion
1 older comment kept for context.
Oluwaseun Adeyemi
CaCO3 + CaO \(\to\) 2CaO + 2CO2
44gm of CO3 is liberated by 100gm of CaCO3
0.33gm of CO2 will be liberated by \(\frac{100}{44}\) x 0.33
= 0.75 of CaCO3
Amount of CaO = 1 - 0.75
= 0.25
% of CaO = \(\frac{0.25}{1} \times \frac{100}{1}\)
= 25%