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Earlier discussion
1 older comment kept for context.
Oluwaseun Adeyemi
The balanced equation of the reaction is:
Pb(NO3)2(aq) + 2HCl(aq) ---> PbCl2(s) + 2HNO3(aq)
From the balanced equation,
1 mole of Pb(NO3)2 gave 1 mole of PbCl2
using, molar concentration = no of moles/volume in dm3
therefore, no of moles = molar concentration x volume in dm3
where, molar concentration of Pb(NO3)2 = 0.1M
volume of Pb(NO3)2 in dm3 = 0.2 dm3
therefore, no of moles of Pb(NO3)2 = 0.1M x 0.2 dm3 = 0.02 mol
but from the balanced equation of the reaction, 1mol of Pb(NO3)2 gave 1mol of PbCl2,
therefore 0.02mol of Pb(NO3)2 will give 0.02mol of PbCl2.
But using, no of moles = mass/molar mass,
therefore mass = no of moles x molar mass
where, no of moles of PbCl2 = 0.02mol
molar mass of PbCl2 = 207 + (2 * 35.5) = 278 g/mol
therefore, mass of PbCl2 = 0.02mol * 278g/mol
= 5.56g
therefore, mass of PbCl2 that precipitated out is 5.56g.
Working and Answer was provided by Chigbundu Emeruwa