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Earlier discussion
1 older comment kept for context.
Magoma peculiar
Molar conc. =no.of moles／Vol in dm3
Vol=250cm3= 0.25dm3
Molar conc=0.5M
No of moles=molar conc Vol in dm3
=0.50.25
=0.125mole of HCl
2moles of HCl → １Mole of Mg
0.125 mole →(0.1251)/2
=0.0625mole of Mg
Reacting mass=no of moles molar mass
Mg=24
Mass=0.0625*24
=1.5g