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Earlier discussion
1 older comment kept for context.
Oluwaseun Adeyemi
CuSO4 \(\to\) Cu2+ + SO42+
Cu2+ + 2e \(\to\) Cu
1 Faraday will deposit \(\frac{64}{2}\)gms of copper
0.1 faraday will deposit \(\frac{64}{2} \times \frac{1}{10} = \frac{64}{20}\)
= \(\frac{32}{10}\) = 3.2gms