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ChemistryJAMB UTME1981

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Earlier discussion

1 older comment kept for context.

Oluwaseun Adeyemi

1.95 gms of NaCl dissolves in 5 cm solution at 30°C

Number of gm of solute required to dissolve in

100 gm = (1.950 x 100)/ (5 x 1) = 1.95 x 20 = 39.0

390 gms will dissolve in 1000 dm3

Solution

Solubility of NaCl at 30°C in

(dm3 is 390)/(Mol wt g NaCl) = 6.67 mol dm3