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Earlier discussion
1 older comment kept for context.
Oluwaseun Adeyemi
In the reactant;
Cu2S
2 Cu - 2(1) = 0
2 Cu = 2
Cu = \(\frac{2}{2}\)
Cu = +1
In the product, Cu
Cu = O
The oxidation number of Cu in Cu2S and Cu respectively is +1 and 0 respectively