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Earlier discussion
1 older comment kept for context.
Oluwaseun Adeyemi
CxHy + (x + y/4)O2 = XCO2 + (y/2)H2O
4.4 2.7
according to the equation 44x = 9y
Carbon Hydrogen
mole given ratio = (44)/(44), (2.7)/(9) = 0.1,0.3
Empirical formula = (0.1)/(0.1), (0.3)/(o.1) = 1,3 ; CH3