Options:
A.
B.
C.
D.
E.
Sign in to view the correct answer and detailed explanation.
Study with fewer interruptions on Android
Use Ulearngo on a verified device for smoother past-question study.
Ulearngo is an independent study app. It is not affiliated with, endorsed by, or representing National Examinations Council (NECO). Always confirm official exam, admission, registration, syllabus, timetable, and result information from NECO official website.
Earlier discussion
1 older comment kept for context.
Pirisola Ayomikun
This is Second law of Michael Faraday in electrolysis.
Since the same quantity of electricity (96500C) will pass through both element, then use the formula
M1Q1/MM1 = M1Q2/MM2
Where M1 = mass of zinc (6.5g)
Q1 = charge on zinc (+2)
MM1 = Molar mass of Zinc
M2 = mass of copper = ?
Q2 = charge on copper = +2
MM2 = Molar mass of Copper
Substituting our values and making M2 subject of the formula,
M2 = M1Q1 MM2/Q2MM1
M2 = 6.5g × 2 × 64g/mol/2 × 65g/mol
M2 = 832g/130
M2 = 6.4
Mass of copper deposited = 6.4g