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ChemistryNECO SSCE1998

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Earlier discussion

3 older comments kept for context.

Quadri Precious

Q=IT
Q=1.00×965
Q=965.0 columns of electricity.
1F=96500c
Cu²+ +2e-=Cu
2F=63.5g of Cu
2×96500=63.5g of Cu
965.0=x
(Cross multiply)
6.35×965.0=2×96500× x
61277.5=193000 x
(Divide both side by the co-efficient)
X=0.32g.

Emmanuel Ehis

Mg = \( \frac{MIt}{ne-} \)

Ganiyu Amudat

(Cu^2+) + (2e^-) = Cu
2 moles of electrons = 2f = 2×96500
Q=It
Q=1×965
Q=965c
63•5g of Cu = 2×96500
x = 965
( Cross multiplying)
x =(63•5 ×965) ÷ 193000
x = 61277•5 ÷ 193000
x = 0•3175
x ~ 0•32g of Cu