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Earlier discussion
1 older comment kept for context.
Pirisola Ayomikun
Given that,
Current (I) = 2.6A
Time (t) = 40mins = 40×60 = 2400s
IF = 96500Cmol-¹
Ar of Silver = 108
Q = it
Q = 2.6 × 2400s
Q = 6240C
Equation of reaction,
AgCl ===> Ag^+ + Cl^–
At the cathode
Ag^+ + e^– ==> Ag(s)
1 F = 1 mole of Silver
Mass = Q/nF × Atomic mass of Silver
nF = number of faraday = 1F = 96500C
Mass = 6240/1×96500 × 108
Mass = 673920/96500
Mass = 6.98g