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Earlier discussion
1 older comment kept for context.
Chinwuba Ebuka
Using dilution factor \(C_1V_1 = C_2V_2\)
Where \(C_1\) is concentration 1 in mol per dm\(^3\)
\(C_2\) is concentration 2 in mol per dm\(^3\)
\(V_1\) is volume 1
\(V_2\) is volume 2
Therefore it can be deduced as
\(0.750 \times V_1 = 250 \times 0.025\)
\(V_1 = \cfrac{6.25}{0.75}\)
\(V_1 = 8.333\) cm\(^3\)