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Earlier discussion
6 older comments kept for context.
Pirisola Ayomikun
Relative Molecular Mass of ZnSO4.7H2O =
Ar of Zn + Ar of S + 4(Ar of O) + 14(Ar of H) + 7(Ar of O)
Note: Ar = Atomic mass
Zn = 65, S = 32, O = 16, H = 1
Therefore,
65 + 32 + 4(16)+14(1)+7(16) = 65 + 32 + 64 + 14 + 112 = 287
Percentage of water of crystallization= Molar mass of 7H2O/Molar mass of ZnSO4.7H2O × 100
= 14 + 112/287 × 100
= 126/287 × 100
= 0.439 × 100
= 43.9
Approximately = 44%
Abraham Ejeh
MM of ZnSO4.7H2O=287
Mass of water of crystallization =126
Using the formula
% of water of crystallization =126/287 ×100/1
=43.91%
approximately 44%
BUKOLA BLESSING
Molecular mass of ZnSo4.7H2O = 65 + 32 + 16 × 4 + 7(1 × 2 + 16)
= 97 + 64 + 126
= 287 grams.
Mass of Water of crystallization inZnSo4.7H2O (7H2O) = 7 × 18
= 126 grams.
Using the Formula,
% of Water of Crystallization
= (Mass of Water of Crystallization/Mass ofZnSo4.7H2O) × 100
= (126/287) × 100
= 43.91%.
Thus, the % of Water of Crystallization inZnSo4.7H2O is 43.91%.
Aisha Okuboye
Zn= 65, S=32, O= 16
The molar mass of water is:
7(2)+7(16)= 126g/mol
The molar mass of the compound is:
65+32+4(16)+7(2)+7(16)= 287g/mol
Then the percentage of water is:
126/287×100 =43.9%~44%
Fasina Nathaniel
m.m of ZnSO4.7H20= 287
mm of 7H20=126
126/287*100= 43.9
Approximately=44%
Raymon Bakre
Mm of Zn≈65
7(H₂O) = 126
Mm of ZnSO₄ ≈ 161
% of Water of crystallization;
= 126
------------- • 100
(126)+(161)
≈44%