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ChemistryUNICAL Sciences and Medicine Post UTME

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Earlier discussion

2 older comments kept for context.

Chizaram Amamchimnefe

V= 50cm³
Mass= 5.05g
Relative molecular mass of KNO3 = ( 39+14+(316)) = 101
Convert 50cm³ to dm_³ which is
1000cm³ = 1dm_³
50cm³ = 501/1000
= 0.05dm_³
Moles = mass/ molar mass
= 5.05/101 =0.05mole
Solubility= mole/volume
Solubility=0.05mol/0.05dm_³
Solubility=1.0mol/dm_³

Alexandra Alexander

Hi dear
Thanks for the solving
It really helped me a lot
Please, I'll need ur help
Can I have ur Whatsapp number