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Earlier discussion
1 older comment kept for context.
Victor Titus
\(p(blue) = \frac{\text{no of blue balls}}{\text{total no of balls}}\)
= \(\frac{2}{3} = \frac{k}{k + 5}\)
\(3k = 2(k + 5)Â \implies 3k = 2k + 10\)
\(3k - 2k = k = 10\)