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MathematicsJAMB UTME2010

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Earlier discussion

1 older comment kept for context.

Oluwaseun Adeyemi

By comparing y = mx + c with y = -4x + 2, the gradient of y = -4x + 2 is m1 = -4

Let the gradient of the line parallel to the given line be m2,

then, m2 = m1 = -4 (condition for parallelism)

Using: y - y1 = m2(x - x1)

Hence the equation of the parallel line is

y - 3 = -4(x-2)

y - 3 = -4 x + 8

y + 4x = 8 + 3

y + 4x = 11

y + 4x - 11 = 0