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MathematicsJAMB UTME1987

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Earlier discussion

1 older comment kept for context.

Oluwaseun Adeyemi

From the diagram, WYZ = 60o, XYW = 180o - 60o

= 120o

LX = 30o

XWY = 180o - 120o + 30o

XWY = 30o

WXY = XYW = 30o

Side XY = YW

YW = 8m, sin 60o = \(\frac{3}{2}\)

∴ sin 60o = \(\frac{h}{YW}\), sin 60o = \(\frac{h}{8}\)

h = 8 x \(\frac{3}{2}\)

= 4\(\sqrt{3}\)