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MathematicsJAMB UTME2001

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Earlier discussion

2 older comments kept for context.

Onyedikachi Kingsley

8√3cm is wrong
Hypotenus=8cm, tita=30° and adjacent=xcm
Using CAH
cos ø=adj/hyp
Substitute
cos 30°=x/8
x=8cos 30°
x=8×√3/2
x=(8√3)/2
x=4√3cm

Oluwaseun Adeyemi

Hint: Make a sketch of the moving points such that the hypotenuse is 8cm and the adjacent x cm.

Cos 30 = x/8
x = 8 cos 30 = 8√3cm