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Earlier discussion
1 older comment kept for context.
Oluwaseun Adeyemi
1st statement: U6 = 1/2(U12)
a + (n -1)d = 1/2[a + (n-1)d]
a + 5d = a + 11d
2(a + 5d) = a + 11d
2a + 10d = a + 11d
Solving, => a = d
Hence the first term is equal to the common difference