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Earlier discussion
1 older comment kept for context.
Oluwaseun Adeyemi
Let u= x2
du = 2xdx
Let v = sinx
∫dv = ∫ sin x i.e. v = cos x
∫ udv = uv − ∫ vdu
∫ x2 Sin xdx = − x2 Cos x − ∫ (− Cos x)2 × dx
x2 Cos x + 2 ∫ x cos x1 dx
= − x2 Cos x + 2 ∫ x Cos x2 dx
2 ∫ u Cos xdx
Let u = x
du = dx
dv = Cos x
∫dv = ∫ Cos x
∫ x2 Sin x1 dx = − x2 Cos x + 2Sin x − 2Cos x + C
∫ x2 Sin xdx
= − x2 Cos x + 2xSin + 2Cos x + C