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Earlier discussion
1 older comment kept for context.
Oluwaseun Adeyemi
-6 \(\leq\) 4 - 2x < 5 - x
split inequalities into two and solve each part as follows:
-6 \(\leq\) 4 - 2x = -6 - 4 \(\leq\) -2x
-10 \(\leq\) -2x
\(\frac{-10}{-2}\) \(\geq\) \(\frac{-2x}{-2}\)
giving 5 \(\geq\) x or x \(\leq\) 5
4 - 2x < 5 - x
-2x + x < 5 - 4
-x < 1
\(\frac{-x}{-1}\) > \(\frac{1}{-1}\)
giving x > -1 or -1 < x
Combining the two results, gives -1 < x \(\leq\) 5