Sum of interior angles of any polygon is (2n - 4) right angle; n angles of the nonagon = 9 where 3 are equal and 6 other angles = 1110\(^{\circ}\) ( 2 x 9 - 4)90\(^{\circ}\) = (18 - 4)90\(^{\circ}\) = 14 x 90\(^{\circ}\) = 1260\(^{\circ}\) 9 angles = 12600, 6 angles = 1110\(^{\circ}\) Remaining 3 angles = 1260\(^{\circ}\) - 1110\(^{\circ}\) = 150\(^{\circ}\) size of one of the3 angles \(\frac{150}{3}\) = 50\(^{\circ}\)

<img alt="" class="alignnone size-full wp-image-295444" height="191" src="https://data.ulearngo.com/assets/9e572e91-08b4-4c3a-ba2a-2d81c2c5311e" width="300"/>Three angles of a nonagon are equal and the sum of six other angles is 1110\(^{\circ}\). Calculate the size of one of the equal angles.

Earlier discussion