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Earlier discussion
1 older comment kept for context.
Oluwaseun Adeyemi
Profit (P) = \(10x - x^2\)
Maximum profit can be achieved when the differential of profit with respect to number of bags(x) is 0
i.e. \(\cfrac{\delta p}{\delta x}\) = 0
\(\cfrac{\delta p}{\delta x}\) = 10 - 2x = 0
10 = 2x
Then x = \(\cfrac{10}{2}\) = 5