Find the square root of 170 - 20\(\sqrt{30}\)

The number of telephone calls N between two cities A and B varies directly as the population PA, PB respectively and inversely as the square of the distance D between A and B. Which of the following equations represents this relation?

The sum of the progression is 1 + x + x2 + x3 + ......

Arrange and \(\frac{3}{5}\),\(\frac{9}{16}\), \(\frac{34}{59}\) and \(\frac{71}{97}\) in ascending order of magnitude.

Multiply (x + 3y + 5) by (2x2 + 5y + 2)

The sum of 3\(\frac{7}{8}\) and 1\(\frac{1}{3}\) is less than the difference between \(\frac{3}{8}\) and 1\(\frac{2}{3}\) by:

A rectangular picture 6cm by 8cm is enclosed by a frame \(\frac{1}{2}\)cm wide. Calculate the area of the frame.

1978 JAMB UTME Mathematics Past Questions

If x2 + 4 = 0, then x ?

Find the square root of 170 - 20\(\sqrt{30}\)

The number of telephone calls N between two cities A and B varies directly as the population PA, PB respectively and inversely as the square of the distance D between A and B. Which of the following equations represents…

The sum of the progression is 1 + x + x2 + x3 + ......

Arrange and \(\frac{3}{5}\),\(\frac{9}{16}\), \(\frac{34}{59}\) and \(\frac{71}{97}\) in ascending order of magnitude.

Multiply (x + 3y + 5) by (2x2 + 5y + 2)

The sum of 3\(\frac{7}{8}\) and 1\(\frac{1}{3}\) is less than the difference between \(\frac{3}{8}\) and 1\(\frac{2}{3}\) by:

A rectangular picture 6cm by 8cm is enclosed by a frame \(\frac{1}{2}\)cm wide. Calculate the area of the frame.