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Earlier discussion
2 older comments kept for context.
Adaeze Mary Joy
S+5= S(P+Q) + 1(2P-Q)
Comparing coefficients of s
S+5= S(P+Q)
P+Q= 1 (eqn 1)
Comparing coefficients
5= 1(2P-Q)
2P-Q=5 ( eqn2)
Then solve simultaneously or using elimination method u get
P=2 and Q=-1
Sharon
P(S+2)+ Q(S-1)=S+5
If S=1
P(1+2)+Q(1-1)=1+5
P(3)+Q(0)=6
3P=6
P=2
If S=-2
P(S+2)+Q(S-1)=S+5
P(-2+2)+Q(-2-1)=-2+5
P(0)+Q(-3)=3
-3Q=3
Q=-1
Therefore P=2
Q=-1
P+Q =2+(-1) =2-1= 1
Answer is 1