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MathematicsUNILAG Post UTME

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Earlier discussion

2 older comments kept for context.

Pirisola Ayomikun

y = 5x - 3

y = 2x + 9

y = y

y = 5x - 3. . . . eqn 1

y = 2x + 9 . . . . eqn 2

5x - 3 = 2x + 9

Collect Like Terms

5x - 2x = 3 + 9

3x = 12

x = 12/3

x = 4



Sub for y in any of eqn 1 & 2

From eqn 2

y = 2x + 9

y = 2(4) + 9

y = 8 +9

y = 17



Therefore, The coordinates are (4, 17)

Derick

Make it a simultaneous equation:

y - 5x = -3

y - 2x =9

-3x = -12

x = 4

Substitute x in d equation above and

y - 2(4) = 9

y - 8 = 9

y = 17