To find the curved surface area of a right circular cone, we can use the formula:

\[ \text{Curved Surface Area} = \pi r l \]

where \( r \) is the radius and \( l \) is the slant height of the cone.

First, we need to find the slant height \( l \). We can use the Pythagorean theorem, since the radius, height, and slant height form a right triangle:

\[ l = \sqrt{r^2 + h^2} \]

Given:

• Radius \( r = 30 \) cm
• Height \( h = 4 \) cm

Let's calculate the slant height \( l \):

\[ l = \sqrt{30^2 + 4^2} = \sqrt{900 + 16} = \sqrt{916} = 2\sqrt{229} \]

Now, we can find the curved surface area:

\[ \text{Curved Surface Area} = \pi \times 30 \times 2\sqrt{229} = 60\pi\sqrt{229} \]

So, the curved surface area of the cone is \( 60\pi\sqrt{229} \) square centimeters.

Can I get the workings of this question please