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MathematicsUNILORIN Post UTME

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Earlier discussion

2 older comments kept for context.

Timothy Godspower

Percentage error = measurement - actual measurement / Actual measurement × 100
%error = 5%
Actual measurement = 50cm
Measurement = ?
Substituting into equation above we have
5/100 = measurement - 50 / 50
Cross multiply
5 × 50 = 100{M - 50}
250 = 100M - 5000
Collect like terms
250 + 5000 = 100M
5250 = 100M
M = 52.5cm and not 512.5cm
Simple right

Temenu Segun

But According to the formular given
It is
Percentage error = measurement - actual measurement / Actual measurement x 100
But with your working
The (x 100) was not included

Pls any explanation for that