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MathematicsUNILORIN Post UTME

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Earlier discussion

1 older comment kept for context.

Ali Benjamin

Let's break it down step by step:

  1. The tanker discharged 33,000 litres of kerosene.
  2. After selling half of it, the remaining amount is: 33,000 / 2 = 16,500 litres.
  3. Since 2,500 litres is to be left in the tank, the amount to be withdrawn is: 16,500 - 2,500 = 14,000 litres.
  4. The pump siphons at a rate of 250 litres per minute, so to find the time it takes to empty the tank, divide the amount to be withdrawn by the pump's rate: 14,000 litres / 250 litres/minute = 56 minutes.

Therefore, it will take 56 minutes to empty the underground tank, leaving 2,500 litres.