Options:
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B.
C.
D.
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Earlier discussion
1 older comment kept for context.
Isreal Adebayo
Let ibok and sanusi age be x and y respectively
Bayo is double the age of ibok= 2x
And bayo is one third as old as sanusi=1/3 ×y
Sanusi will be 48 years in six years time so it mean sanusi current age is 48- 6= 42
Sanusi age is 42 years
And bayo is 1/3 of y
So bayo age is 1/3 ×42= 14 years
Bayo is twice as old as ibok.
Ibok age will be 14/2 which is 7 years.
Option c is correct!