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MathematicsWAEC SSCE2010

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Earlier discussion

1 older comment kept for context.

Oluwaseun Adeyemi

Area of remaining = Area of rectangle = Area of semi-circle


22 x 8 - \(\frac{1}{2}\)xar2


ehere r - \(\frac{14}{2}\)cm = 7cm


Area of remaining = 176 - \(\frac{1}{2}\) x \(\frac{22}{4}\) x 7 x 7


= 176 - 77


= 99cm2