Options:
A.
B.
C.
D.
Sign in to view the correct answer and detailed explanation.
Ulearngo is an independent study app. It is not affiliated with, endorsed by, or representing Joint Admissions and Matriculation Board (JAMB). Always confirm official exam, admission, registration, syllabus, timetable, and result information from JAMB official website.
Options:
1 older comment kept for context.
Oluwaseun Adeyemi
The stopping potential is the potential required to stop the most energetic photo-emitted electron. From the relation e Vs = K.E,(max) where e is the electron charge, and Vs is the stopping potential => e x Vs = 0.34eV
∴ Vs = (0.34eV) / e = 0.34V
∴ stopping potential = 0.34V