Answer: Opt B
Solution
METHOD 1*
The higher the center of gravity of a body the higher the potential energy
Conversely The lower the center of gravity the lower the potential energy
So... A cone in an unstable equilibrium will have the highest center of gravity (highest potential energy)
Hence.. the potential energy is increased from from zero to maximum
Opt B

METHOD 2
P.e= mgh
From the above expression,,, p.e is directly proportional to height,,,
I.e
P.e~h
Let the p.e and height
At stable EQUILIBRIUM be p.e₁ and h₁
also the p.e and height in an unstable equilibrium be p.e₂ and h₂
So...
h₂>h₁
Dat means
p.e₂>p.e₁
This follows that potential energy at p.e₂ is increased from p.e₁
Hence... Opt B

METHOD 3
Law of conservation of energy
We said energy is transferred from one form to another... We can also say that energy is transferred from a higher potential to a lower potential
Okay... If the cone is in an unstable equilibrium,, when it receive a small force it will do more work (more energy)
Compared to when it's in a stable EQUILIBRIUM
Hence,, the energy is increased from stable to unstable equilibrium
Hence... Opt B