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Earlier discussion
1 older comment kept for context.
Oluwaseun Adeyemi
Distance in 105, using, x = ut + \(\frac{1}{2}\)at2
x = (0 x 10) + (\(\frac{1}{2}\) x 10 x 10 x 10) = 500m
distance in 9s; x - (0 x 9) + (\(\frac{1}{2}\) x 10 x 9 x 9) = 405m
distance in last is = difference
= 500 - 405
= 95m