Ulearngo is an independent study app. It is not affiliated with, endorsed by, or representing Joint Admissions and Matriculation Board (JAMB). Always confirm official exam, admission, registration, syllabus, timetable, and result information from JAMB official website.

PhysicsJAMB UTME2007

Options:

A.
B.
C.
D.
Sign in to view the correct answer and detailed explanation.

Study with fewer interruptions on Android

Use Ulearngo on a verified device for smoother past-question study.

Get Ulearngo on Google Play

Earlier discussion

2 older comments kept for context.

CHISOM EUSTACE

n=Vair/Vglass.......(1)
n=1.5,Vlight=3×10⁸m/s
Substituting in eqn..(1)
1.5=3×10⁸/Vglass
Vglass=3×10⁸/1.5
Vglass=2×10⁸m/s
Then thickness of glass is equivalent to the distance of the glass in which the speed of light must cover which is equal to 0.9cm. Equivalent to 0.009m because the speed of light in glass is in metres.
Having;
Vglass=2×10^⁸
Thickness=Dglass=0.009m
time,t=?
V=d/t becomes; Vglass=Dglass/Time
2×10⁸=0.009/Time
Time=0.009/2×10⁸ or Time= 0.009/200000000
Time=4.5×10^-11 or 0.000000000045.

Oluwaseun Adeyemi

N = 1.5 = (speed of light in glass)/speed of light in air

(1.5)/1 = (3.0 x 108)/V

V = (3.0 x 108)/1.5

V = 2.0 x 108 ms-1

But x = Vt

t = (x)/Vt

t = (x)/v = (9 x 10)4/2.0x 108 = 4.5 x 10-2S

∴ Time = 4.5 x 10-12S