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PhysicsJAMB UTME2003

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Earlier discussion

1 older comment kept for context.

Oluwaseun Adeyemi

Generally in thermal/heat conduction, if 1.2 x 106 J is the heat flow per seconds; 30KM-1 is the temperature gradient of the materials; and 400Wm-1K-1 the thermal conductivity of the material, then we have that:

heat flow per seconds per unit area = thermal conductivity x temp. gradient

i.e = 1.2 x 106Area

= 400 x 30

=> 400 x 30 x Area = 1.2 x 106

∴ Area = 1.2 x 106400 x 30

Area = 100m2 or 1.0 x 102m2