Ulearngo is an independent study app. It is not affiliated with, endorsed by, or representing Joint Admissions and Matriculation Board (JAMB). Always confirm official exam, admission, registration, syllabus, timetable, and result information from JAMB official website.

PhysicsJAMB UTME2017

Options:

A.
B.
C.
D.
Sign in to view the correct answer and detailed explanation.

Study with fewer interruptions on Android

Use Ulearngo on a verified device for smoother past-question study.

Get Ulearngo on Google Play

Earlier discussion

2 older comments kept for context.

Johnson

103 * 50 * 10 ^(-6) = 5150 * (10^ (-6))
= 0.00515kg
Force = 5150 * (10^(-5)) N
= 0.0515N

Oluwaseun Adeyemi

Upthrust = change in weight


density = \(\frac{\text{mass}}{\text{volume}}\)


Mass of liquid displaced = Density of Liquid × Volume;


= 103 × 50 × 10− 6m3


= 0.05kg


(Note that the volume of 50cm3 was converted to m3 by multiplying by 106) i.e 50cm3 = 50 × 10−6m3)


Since mass displaced = 0.05kg


Upthrust = mg = 0.05 × 10


= 0.5N