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PhysicsJAMB UTME

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Earlier discussion

3 older comments kept for context.

Dr. Joseph Udoh

No need for long Calculation: just use equation of motion. V²=U²+2as
Since U=0. V=5; a=10; and S=?
Therefore, 5²=2x10s
25= 20s
S= 25/20= 1.25
S = 1.3 approximately

Maxjoe

No need for long Calculation: just use equation of motion. V²=U²+2as
Since U=0. V=5; a=10; and S=?
Therefore, 5²=2x10s
25= 20s
S= 25/20= 1.25
S = 1.3 approximately

Idowu Taye Ebenezer

Let's start from K.E = P.E:

\(\text{mgh} = \frac{1}{2}\text{mv}^2\)

\(\text{mgh} = \cfrac{\text{mv}^2}{2}\)

Cross multiply:

It gives us:

\(2\text{mgh} = \text{mv}^2\)

Divide both sides by m:

It gives:

\(2\text{gh} = \text{v}^2\)

To get the value of h, divide both sides by 2g

The formula to use will become:

\(\text{h} = \cfrac{\text{v}^2}{2\text{g}}\)

Then \(\text{v} = 5\text{ms}^{-1}\)

g = 10. Put this into the above formula:

\(\text{h} = \cfrac{5^2}{2 \times 10}\)

\(\text{h} = \cfrac{25}{20}\)

\(\text{h} = 1.3\text{m}\)