From Faradays Law, mass deposited during electrolysis is given by <br/><br/>M = ItZ<br/><br/>=&gt; Z = M/(It)<br/><table><tbody><tr><td rowspan="2">= </td><td>__2</td></tr><tr><td>0.5x3x60x60</td></tr></tbody></table><br/><br/>For a current of 1.5A flowing for 1h, the mass M, deposited is given by <br/><br/>M= ZiT<br/><br/>= 2 / (0.5x3x60x60) x 0.5x1x60x60 / 1<br/><br/>= 2.0g<br/><br/>M = 2.0g

Assume the same metal ions and current efficiency in both cases. A current of 0.5 A flowing for 3 h deposits 2 g of metal during electrolysis. The quantity of the same metal that would be deposited by a current of 1.5 A flowing for 1 h is

=	__2
	0.5x3x60x60

Earlier discussion