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PhysicsJAMB UTME2004

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Earlier discussion

1 older comment kept for context.

Oluwaseun Adeyemi

Component of 8N along the horizontal = 8 cos 60o = 8 x 0.5

= 4N

Similarity Component of 6N along the horizontal = 6 cos 60o = 3N

∴ Total force towards the right = 10 + 4 + 3

= 17N

Again total force toward the left = 4N

∴ Net horizontal force (towards the right) = 17-4

= 13N