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Earlier discussion
2 older comments kept for context.
Charles
100+273=373
0=273
Solution
340+373=713-273=440
Favour Onwuchekwa
Velocity [V] \( \alpha \)\( \sqrt{Temperature[T]} \)
V = K\( \sqrt{T} \)
K = \( \frac{V}{\sqrt{T}} \)
The equation would be written as;
\( \frac{V_1}{\sqrt{T_1}} = \frac{V_2}{\sqrt{T_2}} \)
Initial velocity = [\( V_1 \)]
Final velocity = [\( V_2 \)] = 340\( ms^{–1} \)
Initial Temperature [\( T_1 \)] = 100°c = 373K
Final Temperature[\( T_2 \)] = 0°c = 273K
\( \frac{V_1}{\sqrt{373}} = \frac{340}{\sqrt{273}} \)
\( \frac{V_1}{\sqrt{373}} = 20.58 \)
\( V_1 \) = 20.58\( \sqrt{373} \)
\( V_1 \) = 397.47
\( V_1 = 397ms^{–1} \)