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Earlier discussion
3 older comments kept for context.
Goodness
Lie lie
Goodness
Vghdh\( \cfrac{a}{b} \)
Oluwaseun Adeyemi
The person's image distance v will be at the distance of 0.1m = 10cm for him to see objects at a distance of u.F = 5.0cm
\( \frac{1}{v} + \frac{1}{u} = \frac{1}{f} \implies \frac{1}{10} + \frac{1}{u} = \frac{1}{5} \\
\frac{1}{u} = \frac{1}{5} - \frac{1}{10} = \frac{2-1}{10} = \frac{1}{10} \\
\text{therefore } u = 10cm = 0.1m \)