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Earlier discussion
1 older comment kept for context.
Oluwaseun Adeyemi
Effective resistance in the circuit
= 3 + 2 + 1 = 6Ω
Current through the I = E/(R+V)
∴I = 2/6
=> V1 = I x R12/6 x 3/1 = 1V
= V2 = I x R2 = 2/6 x 2/1 = 2/3V
∴ we have 1V and 2/3V