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Earlier discussion
1 older comment kept for context.
Oluwaseun Adeyemi
a = 10m/s2, u = 0 t = 10s
The last one second occurs between 9s and 10s.
t1 = 9s and t2 = 10s
S = ut + 1/2at2
u = 0
S = 1/2 at2
The distance covered in the last one second is given by
S = 1/2 a (t22 - t12 )
= 1/2 × 10 × (102 - 92 )
= 0.5 × 10(100 - 81)
= 0.5 × 10 × 19
= 95m