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Earlier discussion
6 older comments kept for context.
Daramola Okikioluwa
Let d be the distance of wall from the boy . Therefore total distance covered by sound to go to wall and come back to boy after reflection from wall , =2d ,
given v=330m/s,t=2s ,
we have , distance=speed×time ,
2d=v×t=330×2 ,
or d=330×2/2=330m
Daniel Jesudarasimi
Velocity = distance /time
The sound wave travelsbthat particular distance twice
So
330=2d/2secs
330×2=2d
330×2/2=d
d=330
Olajide olalekan
x=vt/2
=2×330/2
=330m
Shonde Aishat
The answer supposed to be 330ms^-1
Recall
From....
S=Vt/2
S=330*2/2
S=330m
Oguntoyinbo Taiwo
Yes this 330
ISMAIL AKINLADE
i think it should be 330m