Speed of a Transverse Wave

Speed of a Transverse Wave

Definition: Wave Speed

Wave speed is the distance a wave travels per unit time.

Quantity: Wave speed (\(v\)) Unit name: metre per second Unit symbol: \(\text{m·s$^{-1}$}\)

The distance between two successive crests is \(\text{1}\) wavelength, \(λ\). Thus in a time of \(\text{1}\) period, the wave will travel \(\text{1}\) wavelength in distance. Thus the speed of the wave, \(v\), is:

\[v = \frac{\text{distance travelled}}{\text{time taken}} = \frac{\lambda}{T}\]

However, \(f = \frac{1}{T}\). Therefore, we can also write:

\begin{align*} v & = \frac{\lambda}{T} \\ & = \lambda \cdot \frac{1}{T} \\ & = \lambda \cdot f \end{align*}

We call this equation the wave equation. To summarise, we have that \(v = \lambda \cdot f\) where

  • \(v =\) speed in \(\text{m·s$^{-1}$}\)

  • \(\lambda =\) wavelength in \(\text{m}\)

  • \(f =\) frequency in \(\text{Hz}\)

Wave equation:

\[v = f \cdot \lambda\]

or

\[v = \frac{\lambda}{T}\]

Example:

Question

When a particular string is vibrated at a frequency of \(\text{10}\) \(\text{Hz}\), a transverse wave of wavelength \(\text{0.25}\) \(\text{m}\) is produced. Determine the speed of the wave as it travels along the string.

Step 1: Determine what is given and what is required

  • frequency of wave: \(f = \text{10}\text{ Hz}\)

  • wavelength of wave: \(\lambda = \text{0.25}\text{ m}\)

We are required to calculate the speed of the wave as it travels along the string.

All quantities are in SI units.

Step 2: Determine how to approach the problem

We know that the speed of a wave is:

\[v = f \cdot \lambda\]

and we are given all the necessary quantities.

Step 3: Substituting in the values

\begin{align*} v & = f \cdot \lambda \\ & = (\text{10}\text{ Hz})(\text{0.25}\text{ m}) \\ & = (\text{10}\text{ s$^{-1}$})(\text{0.25}\text{ m}) \\ & = \text{2.5}\text{ m·s$^{-1}$} \end{align*}

Step 4: Write the final answer

The wave travels at \(\text{2.5}\) \(\text{m·s$^{-1}$}\) along the string.

Example:

Question

A cork on the surface of a swimming pool bobs up and down once every second on some ripples. The ripples have a wavelength of \(\text{20}\) \(\text{cm}\). If the cork is \(\text{2}\) \(\text{m}\) from the edge of the pool, how long does it take a ripple passing the cork to reach the edge?

Step 1: Determine what is given and what is required

We are given:

  • frequency of wave: \(f = \text{1}\text{ Hz}\)

  • wavelength of wave: \(\lambda = \text{20}\text{ cm}\)

  • distance of cork from edge of pool: \(D = \text{2}\text{ m}\)

We are required to determine the time it takes for a ripple to travel between the cork and the edge of the pool.

The wavelength is not in SI units and should be converted.

Step 2: Determine how to approach the problem

The time taken for the ripple to reach the edge of the pool is obtained from:

\[t = \frac{D}{v} \qquad \left(\text{from } v = \frac{D}{t}\right)\]

We know that

\[v = f \cdot \lambda\]

Therefore,

\[t = \frac{D}{f \cdot \lambda}\]

Step 3: Convert wavelength to SI units

\[\text{20}\text{ cm} = \text{0.2}\text{ m}\]

Step 4: Solve the problem

\begin{align*} t & = \frac{D}{f \cdot \lambda} \\ & = \frac{\text{2}\text{ m}}{(\text{1}\text{ Hz})(\text{0.2}\text{ m})} \\ & = \frac{\text{2}\text{ m}}{(\text{1}\text{ s$^{-1}$})(\text{0.2}\text{ m})} \\ & = \text{10}\text{ s} \end{align*}

Step 5: Write the final answer

A ripple passing the leaf will take \(\text{10}\) \(\text{s}\) to reach the edge of the pool.

This lesson is part of:

Mechanical Waves and Sound

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