Finding Static Friction
The following examples deal with finding static friction. A box resting on a surface experiences a normal force of magnitude 30 N and the coefficient of static friction between the surface and the box, 0.34. What is the maximum static frictional force? We know ...
The following examples deal with finding static friction.
Example:
Question
A box resting on a surface experiences a normal force of magnitude \(\text{30}\) \(\text{N}\) and the coefficient of static friction tween the surface and the box, \(\mu_s\), is \(\text{0.34}\). What is the maximum static frictional force?
Step 1: Maximum static friction
We know that the relationship between the maximum static friction, \(f_s^{max}\), the coefficient of static friction, \(\mu_s\) and the normal, \(N\), to be:\[f_s^{max} = \mu_sN\]
We have been given that \(\mu_s = \text{0.34}\) and \(N=\text{30}\text{ N}\). This is all of the information required to do the calculation.
Step 2: Calculate the result
\begin{align*} f_s^{max} &= \mu_sN \\ &= (\text{0,34})(\text{30}) \\ & = \text{10,2} \end{align*}
The maximum magnitude of static friction is \(\text{10.2}\) \(\text{N}\).
Example:
Question
The forwards of your school's rugby team are trying to push their scrum machine. The normal force exerted on the scrum machine is \(\text{10 000}\) \(\text{N}\). The machine isn't moving at all. If the coefficient of static friction is \(\text{0.78}\) what is the minimum force they need to exert to get the scrum machine to start moving?
Step 1: Minimum or maximum
The question asks what the minimum force required to get the scrum machine moving will be. We don't know a relationship for this but we do know how to calculate the maximum force of static friction. The forwards need to exert a force greater than this so the minimum amount they can exert is in fact equal to the maximum force of static friction.
Step 2: Maximum static friction
We know that the relationship between the maximum static friction, \(f_s^{max}\), the coefficient of static friction, \(\mu_s\) and the normal, \(N\), to be:\[f_s^{max} = \mu_sN\]
We have been given that \(\mu_s = \text{0.78}\) and \(N=\text{10 000}\text{ N}\). This is all of the information required to do the calculation.
Step 3: Calculate the result
\begin{align*} f_s^{max} &= \mu_sN \\ &= (\text{0,78})(\text{10 000}) \\ & = \text{7 800}\text{ N} \end{align*}
The maximum magnitude of static friction is \(\text{7 800}\) \(\text{N}\).
This lesson is part of:
Newton's Laws