Completing a Table of Solutions to a Linear Equation in Two Variables
Completing a Table of Solutions to a Linear Equation in Two Variables
In the examples above, we substituted the x- and y-values of a given ordered pair to determine whether or not it was a solution to a linear equation. But how do you find the ordered pairs if they are not given? It’s easier than you might think—you can just pick a value for \(x\) and then solve the equation for \(y\). Or, pick a value for \(y\) and then solve for \(x\).
We’ll start by looking at the solutions to the equation \(y=5x-1\) that we found in the last example from the previous lesson. We can summarize this information in a table of solutions, as shown in the table below.
| \(y=5x-1\) | ||
| \(x\) | \(y\) | \(\left(x,y\right)\) |
| 0 | \(-1\) | \(\left(0,-1\right)\) |
| 1 | 4 | \(\left(1,4\right)\) |
To find a third solution, we’ll let \(x=2\) and solve for \(y\).
The ordered pair \(\left(2,9\right)\) is a solution to \(y=5x-1\). We will add it to the table below.
| \(y=5x-1\) | ||
| \(x\) | \(y\) | \(\left(x,y\right)\) |
| 0 | \(-1\) | \(\left(0,-1\right)\) |
| 1 | 4 | \(\left(1,4\right)\) |
| 2 | 9 | \(\left(2,9\right)\) |
We can find more solutions to the equation by substituting in any value of \(x\) or any value of \(y\) and solving the resulting equation to get another ordered pair that is a solution. There are infinitely many solutions of this equation.
Example
Complete the table below to find three solutions to the equation \(y=4x-2\).
| \(y=4x-2\) | ||
| \(x\) | \(y\) | \(\left(x,y\right)\) |
| 0 | ||
| \(-1\) | ||
| 2 | ||
Solution
Substitute \(x=0\), \(x=-1\), and \(x=2\) into \(y=4x-2\).
The results are summarized in the table below.
| \(y=4x-2\) | ||
| \(x\) | \(y\) | \(\left(x,y\right)\) |
| 0 | \(-2\) | \(\left(0,-2\right)\) |
| \(-1\) | \(-6\) | \(\left(-1,-6\right)\) |
| 2 | 6 | \(\left(2,6\right)\) |
Example
Complete the table below to find three solutions to the equation \(5x-4y=20\).
| \(5x-4y=20\) | ||
| \(x\) | \(y\) | \(\left(x,y\right)\) |
| 0 | ||
| 0 | ||
| 5 | ||
Solution
Substitute the given value into the equation \(5x-4y=20\) and solve for the other variable. Then, fill in the values in the table.
The results are summarized in the table below.
| \(5x-4y=20\) | ||
| \(x\) | \(y\) | \(\left(x,y\right)\) |
| 0 | \(-5\) | \(\left(0,-5\right)\) |
| 4 | 0 | \(\left(4,0\right)\) |
| 8 | 5 | \(\left(8,5\right)\) |
This lesson is part of:
Graphs and Equations